Design of Concrete Filled Rectangular tubes


Restrictions on Simplified Design Method
a) columns → doubly symmetrical & uniform cross section
b) steel contribution ratio δ → 0.2 ≤ δ ≤ 0.9
c) non-dimensional slenderness λ ≤ 2
d) 0.3% ≤ As/Ac ≤ 6%
e) minimum & maximum cover are restricted
               minimum cover → 40mm
               maximum cover → cz = 0.3h & cy = 0.4b
f) concrete filled sections → can be fabricated without any reinforcement however concrete encased steel secions → minimum As/Ac = 0.3%
g) ratio of depth to width, 0.2 ≤ h/b ≤ 5


Design of Concrete Filled Rectangular tubes
Type Data Check Reference
Composite column specifications  
  Column length L= m Input data
  Effective length y-y Ley= m  
  Effective length z-z Lez= m  
  Column Type Fully Encased  
Design value of actions
  Design axial force Nsd= kN Input data
  Design bending moment        
  about y-y (major) axis My,top,sd= kNm Input data
    My,bot,sd= kNm Input data
  about z-z (minor) axis Mz,top,sd= kNm Input data
    Mz,bot,sd= kNm Input data
 
Material properties
Structural steel Choose the steel grade  
  Characteristic yield strength fy= N/mm2    
  Modulus elastic of steel Ea= N/mm2    
  Partial safety factor Ya=      
  Design strength fyd= N/mm2    
             
Concrete          
  Concrete grade Choose the concrete grade  
  Type of concrete Normal Weight Concrete    
  Characteristic value of compressive strength fck= N/mm2    
  Partial safety factor Yc=      
  Design value of compressive strength fcd= N/mm2    
  Secant modulus of elasticity Ecm= N/mm2    
             
Reinforcement          
  Characteristic yield strength fyk= N/mm2 Input data  
  Partial safety factor Yc=      
  Design yield strength fsd= N/mm2    
  Design value of modulus of elasticity Es= N/mm2    
             
Connectors          
  Diameter d= mm Input data  
  Overall nominal height hsc= mm Input data  
  Ultimate tensile strength fu= N/mm2 Input data  
             
Cross section geometry and section propertises of the selected section
Structural Steel Choose the steel  
  Mass m= kg/m    
  Depth h= mm    
  Width b= mm    
  Thickness t= mm    
  Root radius r= mm    
  Section area Aa= cm2    
  Second moment of area /yy Iay= cm4    
  Elastic modulus /yy Wel,y= cm3    
  Plastic modulus /yy Wpl,y= cm3    
  Second moment of area /zz Iaz= cm3    
  Elastic modulus /zz Wel,z= cm3    
  Plastic modulus /zz Wpl,z= cm3    
  check for local buckling h/t=      
             
Concrete          
  Area of concrete Ac= cm2    
  Second moment of area about major axis: y-y (of columns) Icy= cm4    
  Second moment of area about minor axis: z-z (of columns) Icz= cm4    
             
Reinforcement          
  The number of longitudinal bars n=   Input data  
  Bar diameter d= mm Input data  
  Total section area As= cm2    
  Concrete cover   mm Input data  
    ey=      
    ez=      
  Second moment of total area about major axis: y-y (of columns) Isy= cm4    
  Second moment of total area about minor axis: z-z (of columns) Isz= cm4    
  Reinforcement ratio As/Ac=      
             
             
 
Plastic resistance of the composite cross section to compression:
  Npl,Rd= kN    
  Steel contribution factor δ=      
Checking long term loading:
Efective elastic flexural stiffness:
  Ec,ef= N/mm2    
  φt=   Input data  
  assuming permanent load is % of design load NG,Ed= kN Input data  
  About the minor axis (y-y):          
  Ke=   Input data  
  (EI)ey= kNm2    
             
  About the minor axis (z-z):          
  Ke=   Input data  
  (EI)ey= kNm2    
Elastic buckling load:
  About the major axis (y-y):          
  Ncry= kN    
  About the minor axis (z-z):          
  Ncrz= kN    
Plastic resistance to compression:
  Npl,Rk= kN    
Non-dimesional slenderness ration:
  About the major axis (y-y):          
       
  About the minor axis (z-z):          
       
             
Evaluate the resistance of the composite column under axial compression:
  Reduction factor:          
  strut curve b for major axis and strut curve c for minor axis          
  y-y axis          
  ay=   Input data  
fy=      
χy=      
         
  z-z axis az=   Input data  
    fz=      
    χz=      
  Where: a is the imperfection parameter which allows for different levels of imperfections in the columns  
             
         
             
Checking Resistance of composite section to under combined compression
  Major axis bending (y-y):          
  Wps: Plastic section modulus for reinforcement          
  Wps= cm3    
  Wpsn: Plastic section modulus for reinforcement within the region of 2hn from the middle line    
  Wpsn= cm3 Check  
  Neutral axis position:          
  hn= mm    
  ez= mm    
             
  Wpc: Plastic section modulus for concrete:          
  Wpc= cm3    
  Wpan: Plastic section modulus of steel within the region of 2hn from the middle line:    
  Wpan= cm3    
  Wpcn: Plastic section modulus of concrete within the region of 2hn from the middle line:    
  Wpcn= cm3    
  The bending resistance          
  Mmax,Rd= kNm    
  Mpl,Rd= kNm    
  The resistance force          
  Npm,Rd= kN    
             
Interaction Diagram:
  Major axis bending (y-y)          
             
Point            
A Bending Moment M (kNm) M=0 MA= kNm    
Compression force N (kN) N=Npl,Rd NA= kN    
B Bending Moment M (kNm) M=Mpl,Rd MB= kNm    
Compression force N (kN) N=0 NB= kN    
C Bending Moment M (kNm) M=Mpl,Rd MC= kNm    
Compression force N (kN) N=Npm,Rd NC= kN    
D Bending Moment M (kNm) M=Mpm,Rd MD= kNm    
Compression force N (kN) N=0.5Npm,Rd ND= kN    
             
             
             
  Minor axis bending (z-z):          
  Wps: Plastic section modulus for reinforcement          
  Wps= cm3    
  Wpsn: Plastic section modulus for reinforcement within the region of 2hn from the middle line    
  Wpsn= cm3    
  Neutral axis position:          
  hn= mm    
  ey= mm    
  Wpc: Plastic section modulus for concrete:          
  Wpc= cm3    
  Wpan: Plastic section modulus of steel within the region of 2hn from the middle line:    
  Wpan= cm3    
  Wpcn: Plastic section modulus of concrete within the region of 2hn from the middle line:    
  Wpcn= cm3    
  The bending resistance          
    Mmax,Rd= kNm    
    Mpl,Rd= kNm    
  The resistance force          
    Npm,Rd= kN    
             
Interaction Diagram:    
  Minor axis bending (z-z)          
             
Point            
A Bending Moment M (kNm) M=0 MA= kNm    
Compression force N (kN) N=Npl,Rd NA= kN    
B Bending Moment M (kNm) M=Mpl,Rd MB= kNm    
Compression force N (kN) N=0 NB= kN    
C Bending Moment M (kNm) M=Mpl,Rd MC= kNm    
Compression force N (kN) N=Npm,Rd NC= kN    
D Bending Moment M (kNm) M=Mpm,Rd MD= kNm    
Compression force N (kN) N=0.5Npm,Rd ND= kN    
             
             
             
Checking for combined compression and bending:
  (EI)eff,II,y= kNm2    
  (EI)eff,II,z= kNm2    
    Ke,II=   Input data  
    Ko=   Input data  
             
  Ncr,eff,y= kN    
  Ncr,eff,z= kN    
  for end moment β=   Input data  
  k1,y=      
  k1,z=      
hence for bending moment from menber imperfection β=   Input data  
    k2,y=      
    k2,z=      
    e0,y= m    
    e0,z= m    
  My,Ed= kNm    
    μdy Mpl,y,Rd= kNm    
          as shown in interaction curve  
    My,EddyMpl,y,Rd =      
    αM=   Input data  
             
  Mz,Ed= kNm    
    μdz Mpl,z,Rd= kNm    
          as shown in interaction curve  
    Mz,EddzMpl,z,Rd =      
    αM=   Input data  
             
         
        imperfection only considered in plane in which failure is expected to occur.
Vertical shear
  major axis y-y          
  The vertical shear is          
  Vy,Ed= kN    
  The design shear resistance is          
  Vpl,a,Rd,y= kN    
             
  Minor axis z-z          
  Vz,Ed= kN    
  Vpl,a,Rd,z= kN    
             
Longitudinal shear
  longitudinal shear force is          
  NEd,c= kN    
  longitudinal shear stress       there is no well-established method for calculating longitudinal shear stress, usually based on
  N/mm2    
  perimeter of steel section pa= mm    
  load introduction length lv= mm    
  design shear strength N/mm2    
  if          
  PRd1= kN    
  PRd2= kN    
  hsc/d=      
  α=      
    PRd= kN    
  number of headed studs          
    n=